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Motion In Straight Line

Question
CBSEENPH11026136

A car starts from rest, moves with an acceleration a and then decelerates at a constant rate b for sometimes to come to rest. If the total time taken is t. The maximum velocity of car is given by :

  • a b ta + b 

  • a2 ta + b

  • a ta+ b

  • b2 ta+b

Solution

A.

a b ta + b 

Let car accelerates for time t1 and decelerates for time t2 then

t1 + t2 = t

From  ν = u + at

v = u + at1

at1 = bt2

 t2 =at1b  t1 + at1b =1t11 +ab =tt1 = bta+b  t1 =bta + bMaximum velocity of carv = at1 =a b ta+ b