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Motion In Straight Line

Question
CBSEENPH11026132

Two similar charges having mass m and 2m are placed in an electric field. The ratio of their kinetic energy is :

  • 4:1

  • 1:1

  • 2:1

  • 1:2

Solution

C.

2:1

Force on charged particle is electric field F = q E

 Acceleration a = F m                          =q EmVelocity v=u + a t                = 0+ q Em t  u - initial velocity , v -final velocity        So kinetic energy K = 12mv2                            K  =12m q Em t2Ratio of kinetic energies      =12m1 q Em1 t2 12m2 q Em2 t2     = m2m1      =2 mm     =21Ratio of kinetic energies      = 2:1