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Thermal Properties Of Matter

Question

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A steel scale measures the length of a copper wire as 80.0 cm, when both are at 20C, the calibration temperature for the scale. What would the scale read for the length of the rod when both are at 40°C?
Given α for steel = 11 × 10^-6 per ^oC and
α for Cu = 11×10^-6 per ^oC

80.0096 cm

80.0272 cm

1 cm

25.2 cm

Solution

80.0096 cm

Using the relation

$l_{t} = l_{o}^{'} (1 + αt) = 1 \times [1 + 11 \times 10^{- 6} \times (40^{o} - 20^{o})] = 1.00022 cm Now length of copper rod at 40^{o} C R_{t}^{'} = l_{o}^{'} (1 + α' t) = 80 [1 + 17 \times 10^{- 6} \times (40^{o} - 20^{o})] = 80.02727 cm Now number of cms observed on the scale = \frac{80.0272}{1.00022} = 80.0096$

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Thermal Properties Of Matter

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Thermal Properties Of Matter

Some More Questions From Thermal Properties of Matter Chapter

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Mock Test Series

NCERT Sample Papers

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