-->

Oscillations

Question
CBSEENPH11026120

Equations of motion in the same direction are given by

y1 =2α sinωt -kx   y2 =2α sinωt -kx-θ 

The amplitude of the medium particle will be

  • 2α cosθ

  • 2α cosθ

  • 4α cosθ2

  • 2α cosθ2

Solution

C.

4α cosθ2

The given equations of motion are

y1=2 α  sin ωt - kxy2 =2 α  sin ωt  -kx -θNow the resultant eqation of wave is given byy= y1 + y2y =2α sin ωt - kx  + 2α sin ωt -kx-θy =2α 2 sin ωt - kx +ωt -kx -θ2                                  ×2cos ωt - kx -wt -kx -θ2 y=4α cosθ2 sin ωt -kx -θ2             .....(1)Now compairing equation (1) withy = A sin ωt - kxResultant amplitude isA = 4 α cosθ2