+91-8076753736 [email protected]

-->

Gravitation

Question

Wired Faculty App

For a satellite moving in an orbit around the earth, the ratio of kinetic energy to potential energy is

2

$\frac{1}{2}$

$\frac{1}{\sqrt{2}}$

$\sqrt{2}$

Solution

B.

$\frac{1}{2}$

Given:- Kinetic energy of satellite is half of its potential energy.
Potential energy of satelite

$U = \frac{{GM}_{e} m}{R_{e}}$

Kinetic energy of satellite

$K = \frac{1}{2} \frac{{GM}_{e} m}{R_{e}}$

Thus

$\frac{K}{U} = \frac{1}{2} \frac{{GM}_{e} m}{R_{e}} \times \frac{R_{e}}{{GM}_{e} m} \frac{K}{U} = \frac{1}{2}$

Some More Questions From Gravitation Chapter

A solid sphere is rotating in free space. If the radius of the sphere is increased keeping mass same which one of the following will not be affected?

Which of the following statements is correct?
(a) Centre of the mass of a body always coincides with the centre of gravity of the body.
(b) Centre of the mass of a body is the point at which the total gravitational torque on the body is zero
(c) A couple on a body produce both translational and rotational motion in a body.
(d) Mechanical advantage greater than one means that small effort can be used to lift a large load.

Two astronauts are floating in gravitational free space after having lost contact with their spaceship. The two will:

Mock Test Series

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation