Question
Two boys are standing at the ends A and B of a ground, where AB = a. The boy at B starts running in a direction perpendicular to AB with velocity v1 The boy at A starts running simultaneously with velocity v and catches the other boy in a time t, where t is
Solution
B.
Distance covered by boy A in time t:- AC= vt
Distance covered by boy B in time t
BC = ν1 t
Using Pythagoras theorem
Ac2 = AB2 + BC2
⇒ ( νt )2 = a2 +( ν1t )2
⇒ a2 = ν2 t2 - (ν1t)2
