Waves

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Two vibrating tuning forks produce progressive waves given by y₁ = 4 sin 500 πt and y₂ = 2 sin 506 Πt. Number of beats produced per minute is

360

180

3

60

Solution

180

To reach the solution the given wave equations must be compared with standard equation of progressive wave.

y₁ = 4sin 500 Πt ....(i)

y₂ = 2sin 506 Πt .....(ii)

Comparing Eqs. (i) and (ii) with
y = a sin ωt

We have

$ω_{1} = 500 π \Rightarrow f_{1} = \frac{500 π}{2 π} \Rightarrow f_{1} = 250 beats / s and ω_{2} = 506 π f_{2} = \frac{506 π}{2 π} f_{2} = 253 beats / s Thus, number of beats produced = f_{2} - f_{1} = 253 - 250 = 3 beats / s = 3 \times 60 beats / \min$

number of beats = 180 beats/min

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Waves

Two vibrating tuning forks produce progressive waves given by y₁ = 4 sin 500 πt and y₂ = 2 sin 506 Πt. Number of beats produced per minute is

360

180

3

60

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For Daily Free Study Material Join wiredfaculty

Waves

Two vibrating tuning forks produce progressive waves given by y1 = 4 sin 500 πt and y2 = 2 sin 506 Πt. Number of beats produced per minute is 360 180 3 60

Some More Questions From Waves Chapter

The sound waves after being converted into electrical waves are not transmitted as such because

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Two vibrating tuning forks produce progressive waves given by y₁ = 4 sin 500 πt and y₂ = 2 sin 506 Πt. Number of beats produced per minute is

360

180

3

60