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Waves

Question
CBSEENPH11026140

A person is observing two trains one coming towards him and other leaving with the same
velocity 4 m/s. If their whistling frequencies are 240 Hz each, then the number of beats per second heard  by the person will be : ( if velocity of sound 320 m/s)

  • 3

  • 6

  • 9

  • zero

Solution

B.

6

Observed frequency of first train

n1 =νν - νs× n      =320320 - 4× 240     =320316 × 240     =243 Hz

Observed frequency of second train

n2 = νν - νs   = 320320 -4× 240    = 320216× 240   = 237 hz Number of beats = 243 - 237  Number of beats  = 6