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Mechanical Properties Of Fluids

Question

The kinetic energy of one molecule of a gas at normal temperature and pressure will be (k = 8.31 J/mole K)

1.7×10³ J

10.2×10³ J

3.4×10³ J

6.8×10³ J

Solution

3.4×10³ J

According to kinetic theory, K.E of 1g-mole of an ideal gas

$E = \frac{3}{2} RT$

where R is universal gas constant, T and n are the temperature of the gas and the number of moles respectively.

Hence K.E at normal temperature 0^o C =273 K

$E = \frac{3}{2} \times 8.31 \times 273 = 3.4 \times 10^{3} J$