The ratio of electrostatic and gravitational forces acting between electron and proton separated by a distance 5×10¹¹m will be (charge on electron =1.6×10^-19 C, mass of electron =9.1×10^-31 kg, mass of proton =1.6×10^-27 kg, G=6.7×10^-11 Nm²/kg² )

2.36×10³⁹

2.36×10⁴⁰

2.36×10⁴¹

2.34×10⁴²

Solution

2.36×10³⁹

Gravitational force is the force of mutual attraction between any two objects by virtue of their masses

Coulomb force also called electrostatic force or coulomb interaction, attraction or repulsion of particles or objects because of their electric force.

$Gravitational force F = \frac{{GM}_{1} M_{2}}{r^{2}} F_{G} = \frac{9 \times 10^{9} \times 9.1 \times 10^{- 31} \times 1.6 \times 10^{- 19}}{{(5 \times 10^{- 11})}^{2}} = 3.9 \times 10^{- 47} N Electrostatic force F_{E} = \frac{1}{4 {πε}_{o}} \frac{q_{1} q_{2}}{r^{2}} = \frac{9 \times 10^{9} \times 1.6 \times 10^{- 19} \times 1.6 \times 10^{- 19}}{{(5 \times 10^{- 11})}^{2}} F_{E} = 9.22 \times 10^{- 8} N ∴ \frac{Electrostatic force}{Gravitational force} = \frac{F_{E}}{F_{G}} = \frac{9.22 \times 10^{- 8}}{3.9 \times 10^{- 47}} = 2.36 \times 10^{39}$

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