A cylinder contains 10kg of gas at pressure of 10⁷ N/m². The quantity of gas taken out of the cylinder, if final pressure is 2.5×10⁶ N/m² will be( temperature of gas is constant)

15.2 kg

3.7 kg

zero

7.5 kg

Solution

7.5 kg

Initial mass of the gas m₁=10kg

Initial pressure P₁=10N/m²

Final pressure P₂ =2.5×10⁶ N/m²

According to kinetic theory of gases

$PV = \frac{1}{3} {mc}^{- 2} or p \propto m Hence, \frac{P_{1}}{P_{2}} = \frac{m_{1}}{m_{2}} or \frac{10^{7}}{2.5 \times 1^{6}} = \frac{10}{m_{2}} or m_{2} = 2.5 kg Hence quantity of gas taken out from the cylinder is 10 - 2.5 = 7.5 kg$

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Mechanical Properties Of Fluids

A cylinder contains 10kg of gas at pressure of 10⁷ N/m². The quantity of gas taken out of the cylinder, if final pressure is 2.5×10⁶ N/m² will be( temperature of gas is constant)

15.2 kg

3.7 kg

zero

7.5 kg

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Mechanical Properties Of Fluids

A cylinder contains 10kg of gas at pressure of 107 N/m2. The quantity of gas taken out of the cylinder, if final pressure is 2.5×106 N/m2 will be( temperature of gas is constant) 15.2 kg 3.7 kg zero 7.5 kg

Some More Questions From Mechanical Properties of Fluids Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

A cylinder contains 10kg of gas at pressure of 10⁷ N/m². The quantity of gas taken out of the cylinder, if final pressure is 2.5×10⁶ N/m² will be( temperature of gas is constant)

15.2 kg

3.7 kg

zero

7.5 kg