Question
The earth of mass =6×1024 kg revolves around the sun with an angular velocity of 2×10-7 rad/s in a circular orbit of radius 1.5×108 km. The force exerted by the sun on earth is
6×1019 N
18×1025 N
36×1021 N
27×1039 N
Solution
C.
36×1021 N
Here :- Mass of earth Me =6×1024 kg
Angular velocity of earth ω =2×10-7 rad/sec
Radius of circular orbit R =1.5×108 km
=1.5×1011m
Force exerted on earth by the sun is given by
F= MeRω2
=6×1024×1.5×1011×(2×10-7)2
=3.6×1022
=36×1021 N
