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Physical World

Question

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The dimensions of gravitational constant are

$[{ML}^{3} T^{- 2}]$

$[M^{- 1} L^{2} T^{- 2}]$

$[{ML}^{- 2} T^{2}]$

$[M^{- 1} L^{3} T^{- 2}]$

Solution

$[M^{- 1} L^{3} T^{- 2}]$

$From the formula G = \frac{{FR}^{2}}{m_{1} m_{2}} Dimensions of G = \frac{dimensions of force F \times dimension of {(R)}^{2}}{dimension of mass M \times dimension of mass M} = \frac{[{MLT}^{- 2}] [L^{2}]}{[M] [M]} = [M^{- 1} L^{3} T^{- 2}]$

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Physical World

The dimensions of gravitational constant are

$[{ML}^{3} T^{- 2}]$

$[M^{- 1} L^{2} T^{- 2}]$

$[{ML}^{- 2} T^{2}]$

$[M^{- 1} L^{3} T^{- 2}]$

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For Daily Free Study Material Join wiredfaculty

Physical World

The dimensions of gravitational constant are ML3T-2 M-1L2T-2 ML-2T2 M-1L3T-2

Some More Questions From Physical World Chapter

Dimension of relative density is

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

The dimensions of gravitational constant are

$[{ML}^{3} T^{- 2}]$

$[M^{- 1} L^{2} T^{- 2}]$

$[{ML}^{- 2} T^{2}]$

$[M^{- 1} L^{3} T^{- 2}]$