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Physical World

Question

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The angular velocity of second hand clock, of a clock is

$(\frac{π}{6}) rad s^{- 1}$

$(\frac{π}{60}) rad s^{- 1}$

$(\frac{π}{30}) rad s^{- 1}$

$(\frac{π}{15}) rad s^{- 1}$

Solution

$(\frac{π}{30}) rad s^{- 1}$

$A n g u l a r v e l o c i t y = \frac{∆ θ}{∆ t} = \frac{2 π}{60} rad s^{- 1} = \frac{π}{30} rad s^{- 1} Reason : - A second hand makes an angle of 2 π (i . e 360^{0}) in one minute (i . e 60 second)$

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Physical World

The angular velocity of second hand clock, of a clock is

$(\frac{π}{6}) rad s^{- 1}$

$(\frac{π}{60}) rad s^{- 1}$

$(\frac{π}{30}) rad s^{- 1}$

$(\frac{π}{15}) rad s^{- 1}$

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Physical World

The angular velocity of second hand clock, of a clock is π6rad s-1 π60rad s-1 π30rad s-1 π15rad s-1

Some More Questions From Physical World Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

The angular velocity of second hand clock, of a clock is

$(\frac{π}{6}) rad s^{- 1}$

$(\frac{π}{60}) rad s^{- 1}$

$(\frac{π}{30}) rad s^{- 1}$

$(\frac{π}{15}) rad s^{- 1}$