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Physical World

Question

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If force $\vec{F} = 5 \hat{i} + 3 \hat{j} + 4 \hat{k}$ makes a displacement of $\vec{s} = 6 \hat{i} - 5 \hat{k}$ work done by the force is

10units

$122 \sqrt{5}$ units

$5 \sqrt{122} units$

20units

Solution

10units

$Work done = F o r c e \times d i s p l a c e m e n t = \vec{F} . \vec{s} = (5 \hat{i} + 3 \hat{j} + 4 \hat{k}) . (6 \hat{i} - 5 \hat{k}) = (5 \hat{i} + 3 \hat{j} + 4 \hat{k}) . (6 \hat{i} + 0 \hat{j} - 5 \hat{k}) = (30 + 0 - 20) = 10 units$

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Physical World

If force $\vec{F} = 5 \hat{i} + 3 \hat{j} + 4 \hat{k}$ makes a displacement of $\vec{s} = 6 \hat{i} - 5 \hat{k}$ work done by the force is

10units

$122 \sqrt{5}$ units

$5 \sqrt{122} units$

20units

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Physical World

If force F→=5i^+3j^+4k^ makes a displacement of s→=6i^-5k^work done by the force is 10units 1225units 5122units 20units

Some More Questions From Physical World Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

If force $\vec{F} = 5 \hat{i} + 3 \hat{j} + 4 \hat{k}$ makes a displacement of $\vec{s} = 6 \hat{i} - 5 \hat{k}$ work done by the force is

10units

$122 \sqrt{5}$ units

$5 \sqrt{122} units$

20units