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Physical World

Question

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A man is at height of 100 m. he sees a car which makes an angle of $\frac{π}{6}$ with man's position. If the car moves to a point where angle is $\frac{π}{3}$ what is the distance moved by it?

$(\frac{100}{\sqrt{3}}) m$

$(200 \sqrt{3}) m$

$(\frac{200}{\sqrt{3}}) m$

$(\frac{150}{\sqrt{3}}) m$

Solution

$(\frac{200}{\sqrt{3}}) m$

$In ∆ ABC \tan 60^{0} = \frac{100}{x} \Rightarrow x = \frac{100}{\sqrt{3}} . . . . . (1) In ∆ ABD \tan 30^{0} = \frac{100}{x + y} \Rightarrow x + y = 100 \sqrt{3} \Rightarrow y = 100 \sqrt{3} - \frac{100}{\sqrt{3}} from (1) = \frac{200}{\sqrt{3}} m$

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Physical World

A man is at height of 100 m. he sees a car which makes an angle of $\frac{π}{6}$ with man's position. If the car moves to a point where angle is $\frac{π}{3}$ what is the distance moved by it?

$(\frac{100}{\sqrt{3}}) m$

$(200 \sqrt{3}) m$

$(\frac{200}{\sqrt{3}}) m$

$(\frac{150}{\sqrt{3}}) m$

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Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

A man is at height of 100 m. he sees a car which makes an angle of $\frac{π}{6}$ with man's position. If the car moves to a point where angle is $\frac{π}{3}$ what is the distance moved by it?

$(\frac{100}{\sqrt{3}}) m$

$(200 \sqrt{3}) m$

$(\frac{200}{\sqrt{3}}) m$

$(\frac{150}{\sqrt{3}}) m$