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Mechanical Properties Of Fluids

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Energy is being emitted from the surface of a black body at 127°C the rate of 1.0 x 10⁶ J/sm². The temperature of the black body at which the rate of energy emission is 16.0 x 10° J/sm² will be

754⁰C

527⁰C

254⁰C

508⁰C

Solution

527⁰C

$\frac{E_{2}}{E_{1}} = {(\frac{T_{1}}{T_{2}})}^{4} (\frac{T_{2}}{T_{1}}) = {(\frac{E_{2}}{E_{1}})}^{1 / 4} = {(\frac{16.0 \times 10^{6}}{1 \times 10^{6}})}^{1 / 4} T_{2} = 2 T_{1} = 2 \times T_{1} = 2 \times 400 = 800 k = 527^{0} C$

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Mechanical Properties Of Fluids

Energy is being emitted from the surface of a black body at 127°C the rate of 1.0 x 10⁶ J/sm². The temperature of the black body at which the rate of energy emission is 16.0 x 10° J/sm² will be

754⁰C

527⁰C

254⁰C

508⁰C

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For Daily Free Study Material Join wiredfaculty

Mechanical Properties Of Fluids

Energy is being emitted from the surface of a black body at 127°C the rate of 1.0 x 106 J/sm2. The temperature of the black body at which the rate of energy emission is 16.0 x 10° J/sm2 will be 7540C 5270C 2540C 5080C

Some More Questions From Mechanical Properties of Fluids Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Energy is being emitted from the surface of a black body at 127°C the rate of 1.0 x 10⁶ J/sm². The temperature of the black body at which the rate of energy emission is 16.0 x 10° J/sm² will be

754⁰C

527⁰C

254⁰C

508⁰C