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Mechanical Properties Of Fluids

Question

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Helium at 27⁰C has a volume 8 litres. it is suddenly compressed to a volume of 1 litre. The temperature of the gas will be $(V = \frac{5}{3})$

9327⁰C

1200⁰C

927⁰C

108⁰C

Solution

927⁰C

${TV}_{1}^{γ - 1} = {TV}_{2}^{γ - 2} T_{2} = (\frac{V_{1}}{V_{2}}) T_{1} T_{2} = {(\frac{V_{1}}{V_{2}})}^{\frac{5}{3} - 2} \times 300 T_{2} = {(\frac{8}{1})}^{\frac{2}{3}} \times 300 = 4 \times 300 = 1200 k T_{2} = 1200 - 273 = 927^{0} C$

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Mechanical Properties Of Fluids

Helium at 27⁰C has a volume 8 litres. it is suddenly compressed to a volume of 1 litre. The temperature of the gas will be $(V = \frac{5}{3})$

9327⁰C

1200⁰C

927⁰C

108⁰C

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Mechanical Properties Of Fluids

Helium at 270C has a volume 8 litres. it is suddenly compressed to a volume of 1 litre. The temperature of the gas will be V= 53 93270C 12000C 9270C 1080C

Some More Questions From Mechanical Properties of Fluids Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Helium at 27⁰C has a volume 8 litres. it is suddenly compressed to a volume of 1 litre. The temperature of the gas will be $(V = \frac{5}{3})$

9327⁰C

1200⁰C

927⁰C

108⁰C