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Mechanical Properties Of Fluids

Question

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The root mean square velocity of hydrogen molecules of an ideal hydrogen gas kept in a gas chamber at 0C is 3180 m/s. Calculate the pressure of hydrogen gas: $(Density of hydrogen gas = 8.99 \times 10^{- 2} \frac{kg}{m^{3}}, atmosphere = 1.01 \times 10^{5} \frac{N}{m^{2}})$

3.0atm

2.0atm

1.5atm

1.0atm

Solution

3.0atm

$P = \frac{1}{3} {ρν}_{rms}^{2} = \frac{1}{3} \times 8.99 \times 10^{- 2} \times {(3180)}^{2} = \frac{1}{3} \times \frac{8.99 \times 10^{- 2} \times {(3180)}^{2}}{1.01 \times 10^{5}} atm P = 3 atm$

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Mechanical Properties Of Fluids

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Mechanical Properties Of Fluids

The root mean square velocity of hydrogen molecules of an ideal hydrogen gas kept in a gas chamber at 0C is 3180 m/s. Calculate the pressure of hydrogen gas:Density of hydrogen gas=8.99×10-2kgm3, atmosphere= 1.01×105Nm2 3.0atm 2.0atm 1.5atm 1.0atm

Some More Questions From Mechanical Properties of Fluids Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation