The equation of travelling wave is y= 60 cos (1800 t-6x) where y is in micron and t in second and x in metre. The ratio of maximum particle velocity to velocity of wave propagation is

3.6

3.6 $\times 10^{- 4}$

$3.6 \times 10^{- 11}$

$3.6 \times 10^{- 6}$

Solution

3.6 $\times 10^{- 4}$

$y (x, t) = A \sin (kx - ωt + ϕ) the equation is y = 60 \cos (1800 t - 6 x) Velocity of the wave is given by ν = \frac{ω}{k} = \frac{1800}{6} = 3.6 \times 10^{- 4} Maximum particle velocity is u_{\max} = Aω = 60 \times 10^{- 6} \times 1800 m / s (as t in second, x in meter and y is in micron so A = 60 \times 10^{- 6}) The ratio is u_{\max} = \frac{60 \times 10^{- 6} \times 1800}{300} = 3.6 \times 10^{- 4}$

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Mechanical Properties Of Fluids

The equation of travelling wave is y= 60 cos (1800 t-6x) where y is in micron and t in second and x in metre. The ratio of maximum particle velocity to velocity of wave propagation is

3.6

3.6 $\times 10^{- 4}$

$3.6 \times 10^{- 11}$

$3.6 \times 10^{- 6}$

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Mechanical Properties Of Fluids

The equation of travelling wave is y= 60 cos (1800 t-6x) where y is in micron and t in second and x in metre. The ratio of maximum particle velocity to velocity of wave propagation is 3.6 3.6×10-4 3.6×10-11 3.6×10-6

Some More Questions From Mechanical Properties of Fluids Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

The equation of travelling wave is y= 60 cos (1800 t-6x) where y is in micron and t in second and x in metre. The ratio of maximum particle velocity to velocity of wave propagation is

3.6

3.6 $\times 10^{- 4}$

$3.6 \times 10^{- 11}$

$3.6 \times 10^{- 6}$