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Mechanical Properties Of Fluids

Question

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A steel wire 0.5 m long has a total mass 0.01 kg and stretched with a tension of 800 N. The frequency with which it vibrates in its fundamental note will be

4Hz

2Hz

200Hz

160Hz

Solution

200Hz

$Given \to length of wire L = 0.5 m, tension on wire t = 800 N m = \frac{M}{L} = \frac{0.01}{0.5} kg / m Fundamental frequency is n = \frac{1}{2 L} \sqrt{\frac{T}{m}} = \frac{1}{2 \times 0.5} \sqrt{\frac{800 \times 0.5}{0.01}} n = 200 Hz$

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Mechanical Properties Of Fluids

A steel wire 0.5 m long has a total mass 0.01 kg and stretched with a tension of 800 N. The frequency with which it vibrates in its fundamental note will be

4Hz

2Hz

200Hz

160Hz

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For Daily Free Study Material Join wiredfaculty

Mechanical Properties Of Fluids

A steel wire 0.5 m long has a total mass 0.01 kg and stretched with a tension of 800 N. The frequency with which it vibrates in its fundamental note will be 4Hz 2Hz 200Hz 160Hz

Some More Questions From Mechanical Properties of Fluids Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

A steel wire 0.5 m long has a total mass 0.01 kg and stretched with a tension of 800 N. The frequency with which it vibrates in its fundamental note will be

4Hz

2Hz

200Hz

160Hz