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Mechanical Properties Of Fluids

Question

Standing wave are produced in a 10 m long stretched string. If the string vibrates in 5 segments and the wave velocity is 20 m/s. The frequency is

10Hz

5Hz

4Hz

2Hz

Solution

5Hz

$n = \frac{p}{2 l} \sqrt{\frac{T}{m}} = \frac{pν}{2 l} where l is the length of the stretched string = \frac{5 \times 20}{2 \times 10} n = 5 Hz$