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Mechanical Properties Of Fluids

Question

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The soap bubbles have radii in the ratio 2: 1 ratio of excess pressure in side there is

1:4

4:1

2:1

1:2

Solution

1:2

$P \propto \frac{1}{r} hence, \frac{P_{1}}{P_{2}} = \frac{\frac{1}{r_{1}}}{\frac{1}{r_{2}}} = \frac{r_{2}}{r_{1}} = \frac{1}{2} . . . since r_{1} : r_{2} = 2 : 1 P_{1} : P_{2} = 1 : 2$

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Mechanical Properties Of Fluids

The soap bubbles have radii in the ratio 2: 1 ratio of excess pressure in side there is

1:4

4:1

2:1

1:2

Some More Questions From Mechanical Properties of Fluids Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

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For Daily Free Study Material Join wiredfaculty

Mechanical Properties Of Fluids

The soap bubbles have radii in the ratio 2: 1 ratio of excess pressure in side there is 1:4 4:1 2:1 1:2

Some More Questions From Mechanical Properties of Fluids Chapter

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

The soap bubbles have radii in the ratio 2: 1 ratio of excess pressure in side there is

1:4

4:1

2:1

1:2