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Mechanical Properties Of Fluids

Question

A capillary tube of radius r can support a liquid of weight 6.28 x 10^-4 N. If the surface tension of the liquid is 5 x 10^-2N/m. The radius of capillary must be

$2.0 \times 10^{- 3} m$

$2.0 \times 10^{- 4}$ m

1.5 $\times 10^{- 3} m$

$12.5 \times 10^{- 4} m$

Solution

$2.0 \times 10^{- 3} m$

Given:- weight =6.24 $\times$ 10^-4N,

W=T. $2 πr$

r= $\frac{W}{2 πT}$ = $\frac{6.28 \times 10^{- 4}}{2 \times 3.14 \times 5 \times 10^{- 2}}$

r = 2 $\times 10^{- 3}$ m