A wheel rotates with constant acceleration of 2.0 radian/sec² .If the wheel starts from rest the number of revolution it makes in the first ten second, will be approximately

32

24

16

8

Solution

Angular acceleration= 2 rad/s²

Time interval t= 10sec

Angular displacement θ = ?

$N ow by θ = ωt + \frac{1}{2} {αt}^{2} . . . . (i) [It is an equation of angular variables of motion corresponding to the linear variable based equations s] (s = ut + \frac{1}{2} {αt}^{2}) (i) \Rightarrow θ = 0 + \frac{1}{2} {αt}^{2} θ = \frac{{αt}^{2}}{2} = \frac{2 \times 100}{2} = 100 n = \frac{θ}{2 π} = \frac{100}{2 \times 3.14} = 15.92 \approx 16$

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Physical World

A wheel rotates with constant acceleration of 2.0 radian/sec² .If the wheel starts from rest the number of revolution it makes in the first ten second, will be approximately

32

24

16

8

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Physical World

A wheel rotates with constant acceleration of 2.0 radian/sec2 .If the wheel starts from rest the number of revolution it makes in the first ten second, will be approximately 32 24 16 8

Some More Questions From Physical World Chapter

Dimension of relative density is

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

A wheel rotates with constant acceleration of 2.0 radian/sec² .If the wheel starts from rest the number of revolution it makes in the first ten second, will be approximately

32

24

16

8