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Physical World

Question

A car of mass 1000 kg moves on a circular track of radius 20 m. If the coefficient of friction of 0.64. The maximum velocity with which the car can be moved is

11.2m/s

112m/s

$\frac{0.64 \times 20}{1000 \times 100} m / s$

$\frac{1000}{64 \times 20} m / s$

Solution

11.2m/s

$V_{\max} = \sqrt{μrg} = \sqrt{0.64 \times 20 \times 9.8} where, μ - coefficient of friction V_{\max} = 11.2 m / s$