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Gravitation

Question
CBSEENPH11020867

A thin symmertical double convex lens of refractive index μ2 = 1.5 is placed between a medium of refractive index μ1 = 1.4 to the left and another medium of refractive index μ3 = 1.6 to the right. Then, the system behaves as

  • a convex lens

  • a concave lens

  • a glass plate

  • a convexo-concave lens

Solution

C.

a glass plate

For the first refracting surface,

For a parallel beam of light; 

-μu + μ2V = μ2-1R = 1.4- + 1.5V = 1.5 - 1.4RV = 15 R

For second refracting surface,

μ21.5R + μ3V' = μ3- μ2R - 1.515 R + 1.6V' = 1.6-1.5R V' = 

Hence, the combination behaves as a glass plate.