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Laws Of Motion

Question
CBSEENPH11020859

A cylindrical tube of uniform cross-sectional area A is fitted with two air tight frictionless pistons. The pistons are connected to each other by a metallic wire. Initially, the pressure of the gas is p0 and temperature is T0, atmospheric pressure is also p0. Now, the temperature of the gas is increased to 2T0, the tension of the wire will be

  • 2p0A

  • p0A

  • p0A/2

  • 4p0A

Solution

B.

p0A

The volume of the gas is constant i.e., V = constant

∴ p ∝ T i.e pressure will be doubled if the temperature is doubled.

Let F be the tension in the wire. Then, the equilibrium of anyone pipes gives.

F = (p-p0) A = 2(p0 - p0) = p0A