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Laws Of Motion

Question

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A block of mass m is placed on a smooth inclined wedge ABC of inclination θ as shown in the figure. The wedge is given an acceleration 'a' towards the right. The relation between a and θ for the block to remain stationary on the wedge is

$a = \frac{g}{\cos e c θ}$

$a = \frac{g}{\sin θ}$

a = g tan θ

a = g cos θ

Solution

C.

a = g tan θ

In non-inertial frame,

N sin θ = ma ...(i)
N cos θ = mg... (ii)

tan θ = a/g
a = g tan θ

Some More Questions From Laws of Motion Chapter

Define inertia.

When the branches of an apple tree are shaken, the apples fall down. Why?

A person jumping out from a moving car or bus falls forward. Why?

Due to what type of inertia, the spark leaves the grind stone tangentially while sharpening the knife?

Which law of motion is also called law of inertia?

What is measure of inertia of body?

Which law of motion defines the force?

What happens to a stone tied to the end of string and whirled in a circle if the string suddenly breaks?

Which law of motion gives the quantitative knowledge of force?

Which law of motion is the real law of motion?

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