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Laws Of Motion

Question
CBSEENPH11020849

A body initially at rest and sliding along a frictionless track from a height h (as shown in the figure) just completes a vertical circle of diameter AB = D. The height h is equal to

  • 3D/2

  • D

  • 5D/4

  • 7D/5

Solution

C.

5D/4

As track is frictionless, so total mechanical energy will remain constant,

i.e., 0 + mgh = 12mvL2 + 0using v2 - u2 = 2gh,h = vL22g ( u = 0)For completing the vertical circle VL 5gRor, h = 5gR2g = 52R = 54D