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Oscillations

Question
CBSEENPH11020836

A pendulum is hung from the roof of a sufficiently high building and is moving freely to and fro like a simple harmonic oscillator. The acceleration of the bob of the pendulum is 20 m/s2 at a distance of 5 m from the mean position. The time period of oscillation is

  • 2πs

  • π s

  • 1s

  • 2s

Solution

B.

π s

Acceleration, a = 20 m/s2 , and displacement, y = 5
|a| =ω2y 20 = ω2(5) ω = 2 rad/sTime period of pendulum,T = 2πω = 2π2 = πs