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Motion In Straight Line

Question
CBSEENPH11020793

A particle moves along a straight line OX. At a time t (in seconds) the distance x (in metres) of the particle from O is given by
        straight x equals 40 straight t space plus 12 straight t minus straight t cubed
How long would the particle travel before coming to rest?

  • 24m

  • 40m

  • 56m

  • 16m

Solution

C.

56m

Velocity is rate of change of distance or displacement.
Distance travelled by the particle is
                      straight x equals space 40 space plus 12 straight t minus straight t cubed
We know that, velocity is rate of change of distance i.e., straight v equals dx over dt.
therefore space space space straight v space equals space straight d over dt left parenthesis 40 plus 12 straight t minus straight t cubed right parenthesis
space space space space space space equals space 0 plus 12 minus 3 straight t squared
but final velocity v = 0
therefore space space 12 minus 3 straight t squared space equals space 0
or space space space space space space space space straight t squared space equals space 12 over 3 space equals 4
or space space space space space space straight t space equals space 2 straight s
Hence, distance travelled by the particle before coming to rest is given by
                   straight x equals 40 plus 12 left parenthesis 2 right parenthesis minus left parenthesis 2 right parenthesis cubed
space space equals 40 plus 24 minus 8 space equals space 64 minus 8
space space equals space 56 space straight m