Question
If the cold junction of a thermocouple is kept at 0o C and the hot junction is kept at To C, then the relation between neutral temperature (Tn) and temperature of inversion (Ti) is:
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Tn = 2Ti
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Tn = Ti -T
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Tn = Ti + T
Solution
A.
It is found that temperature of inversion (Ti) is as much above the neutral temperature (Tn) as neutral temperature is above the temperature of the cold junction (T), ie,
Ti -Tn = Tn-T
Ti = 2Tn-T
But, here the cold junction is kept at 0o C, hence
T = 0
Thus, Ti = 2Tn
Or Tn = Ti/2
