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Mechanical Properties Of Fluids

Question
CBSEENPH11020761
Wired Faculty App

At 10o C the value of the density of a fixed mass of an ideal gas divided by its pressure is x. At 110o C this ratio is

  • x

  • 383x/283

  • 10x/110

  • 283x/383

Solution

D.

283x/383

Writing ideal gas law
PV = nRT
PV space equals space straight m over straight M RT PV over straight m space equals space 1 over straight M RT straight P over straight rho space equals space RT over straight M straight rho over straight P space equals space 1 over straight T Therefore comma fraction numerator straight rho subscript 1 divided by straight P subscript 1 over denominator straight rho subscript 2 divided by straight P subscript 2 end fraction space equals space straight T subscript 1 over straight T subscript 2 fraction numerator straight x over denominator left parenthesis straight rho subscript 2 divided by straight P subscript 2 right parenthesis end fraction space equals space 383 over 283 straight rho subscript 2 over straight P subscript 2 space equals space 283 over 383 straight x

Some More Questions From Mechanical Properties of Fluids Chapter

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