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Motion In A Plane

Question
CBSEENPH11020758

A particle of mass is projected with the velocity v making an angle of 45o with the horizontal. 
When the particle  lands on the level ground the magnitude of the change in its momentum will be

  • 2 mv

  • mv divided by square root of 2
  • square root of 2 mv
  • zero

Solution

C.

square root of 2 mv
The horizontal momentum does not change. The change in vertical momentum is 
mv sin θ - (-mv sin θ ) 
=2 space mv fraction numerator 1 over denominator square root of 2 end fraction space equals space square root of 2 space mv