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Laws Of Motion

Question
CBSEENPH11020751

A closed loop PQRS carrying a current is placed in a uniform magnetic field. If the magnetic forces on segments PS, SR and RQ are F1, F2 and F3 respectively and are in the plane of the paper and along the directions shown, the force on the segment of QP is

  • F3 - F1-F2

  • square root of left parenthesis straight F subscript 3 minus straight F subscript 2 right parenthesis squared space plus straight F subscript 2 squared end root
  • square root of left parenthesis straight F subscript 3 minus straight F subscript 1 right parenthesis squared minus straight F subscript 2 squared end root
  • F3 - F2 + F1

Solution

B.

square root of left parenthesis straight F subscript 3 minus straight F subscript 2 right parenthesis squared space plus straight F subscript 2 squared end root
F4 sin θ = F2
F4 cos θ = (F3-F1)
straight F subscript 4 space equals space square root of left parenthesis straight F subscript 3 minus straight F subscript 1 right parenthesis squared space plus straight F subscript 2 squared end root