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Motion In Straight Line

Question
CBSEENPH11020742
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A roller coaster is designed such that riders experience " weightlessness" as they go round the top of a hill whose radius of curvature is 20 m.  The speed of the car at the top of the hill is between

  • 14 m/s and 15 m/s

  • 15m/s and 16 m/s

  • 16 m/s and 17 m/s

  • 13m/s and 17 m/s

Solution

A.

14 m/s and 15 m/s


Balancing the forces, we get
Mg-N = Mv2/R
For weightlessness, N = 0 
therefore, MV2/R = Mg
where R is the radius of curvature and v is the speeds of the car.
Therefore,
straight v space equals square root of Rg putting space the space values comma space straight R space equals space 20 straight m comma space straight g space equals space 10.0 space straight m divided by straight s squared So comma space straight v equals space square root of 20 space straight x space 10.0 end root space equals 14.14 space straight m divided by straight s squared
Thus, the speed of the car at the top of the hill is between 14 m/s and 15 m/s

Some More Questions From Motion in Straight Line Chapter

Is absolute rest or absolute motion possible?

What is the most essential thing to study the motion of a body?

Can a body be always at rest in some frame?

Can a body be in motion in the frame associated with the body itself?

When an object in motion can be considered as particle or point object?

Can you think of physical phenomena involving the moon in which moon cannot be treated as particle?

A train is crossing the bridge. Can it be taken as a particle?

Can a train be taken a particle? Give an example in support of your answer.

 A particle is moving along curved line in space. Is the motion one dimensional?

State which of the following are examples of one, two or three dimensional motion: 

(a) A kite flying in the sky.

(b) The earth revolving around the sun. 

(c) A train moving along the equator of the earth in clockwise direction. 

(d) Accelerated motion of a particle in a straight line.

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