Question

Each on the two strings of length 51.6 cm and 49.1 cm are tensioned separately by 20 N force. Mass per unit length of both the strings is same and equal to 1 gm^-1. When both strings vibrate simultaneously the number of beats is

5

7

8

3

Solution

The number of beats will be the difference of frequencies of the two strings. $frequency space of space first space string space straight f subscript 1 space equals space fraction numerator 1 over denominator 2 straight l subscript 1 end fraction square root of straight T over straight m end root equals space fraction numerator 1 over denominator 2 space straight x 51.6 space straight x space 10 to the power of negative 2 end exponent end fraction square root of 20 over 10 to the power of negative 3 end exponent end root similarly comma space frequency space of space second space string equals space fraction numerator 1 over denominator 2 space straight x space 49.1 space straight x space 10 to the power of negative 2 end exponent end fraction square root of 20 over 10 to the power of negative 3 end exponent end root Number space of space beats space equals space straight f subscript 2 minus straight f subscript 1 space equals space 144 minus 137 equals space 7 space beats$

Some More Questions From Mechanical Properties of Fluids Chapter

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Mechanical Properties Of Fluids

Each on the two strings of length 51.6 cm and 49.1 cm are tensioned separately by 20 N force. Mass per unit length of both the strings is same and equal to 1 gm^-1. When both strings vibrate simultaneously the number of beats is

5

7

8

3

Some More Questions From Mechanical Properties of Fluids Chapter

What is an oscillatory motion?

What is time period?

Define frequency.

What is the condition for motion to be simple harmonic motion?

In the displacement equation y = r sin(ωt/ + ϕ) what does ϕ called and what information does it give?

What determines the natural frequency of an oscillator?

Is there any relation between uniform circular motion and simple harmonic motion?

What is periodic motion?

Write down the expression for the instantaneous velocity and acceleration of particle vibrating in simple harmonic motion.

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For Daily Free Study Material Join wiredfaculty

Mechanical Properties Of Fluids

Each on the two strings of length 51.6 cm and 49.1 cm are tensioned separately by 20 N force. Mass per unit length of both the strings is same and equal to 1 gm-1. When both strings vibrate simultaneously the number of beats is 5 7 8 3

Some More Questions From Mechanical Properties of Fluids Chapter

What is an oscillatory motion?

What is time period?

Define frequency.

What is the condition for motion to be simple harmonic motion?

In the displacement equation y = r sin(ωt/ + ϕ) what does ϕ called and what information does it give?

What determines the natural frequency of an oscillator?

Is there any relation between uniform circular motion and simple harmonic motion?

What is periodic motion?

Write down the expression for the instantaneous velocity and acceleration of particle vibrating in simple harmonic motion.

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

Each on the two strings of length 51.6 cm and 49.1 cm are tensioned separately by 20 N force. Mass per unit length of both the strings is same and equal to 1 gm^-1. When both strings vibrate simultaneously the number of beats is

5

7

8

3