Question
Four identical thin rods each of mass M and length l , inertial form a square frame. moment of inertia of this frame about an axis through the centre of the square and perpendicular to this plane is
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4Ml2/3
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2Ml2/3
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13Ml2/3
-
Ml2/3
Solution
A.
4Ml2/3
Apply theorem of the parallel axis and the total moment of inertia will be the sum of the moment of inertia of each rod.
Moment of inertia of rod about an axis through its centre of mass and perpendicular to rod + (mass) of rod) x (perpendicular distance between two axes)
=