Question
An engine pumps water continuously through a hose. Water leaves the hose with a velocity v and m is the mass per unit length of the water jet. What is the rate at which kinetic energy is imparted to water?
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mv3 /2
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mv3
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mv2/2
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m2v2 /2
Solution
A.
mv3 /2
Let m is the mass per unit length rate of mass per sec = mx/t = mv
Rate of KE = (mv)v2/2 = mv3/2
