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Units And Measurement

Question
CBSEENPH11020705
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From a circular disc of radius R and mass 9M, a small disc of mass M and radius R/3 is removed concentrically. The moment of inertia of the remaining disc about an axis perpendicular to the plane of the disc and passing through its centre is

  • 40MR2/9

  • MR2

  • 4 MR2

  • 4MR2/9

Solution

A.

40MR2/9

The moment of inertia of the remaining disc about axis perpendicular to the plane of the disc and passing through its centre.

straight I space equals space straight I subscript 1 minus straight I subscript italic 2 space equals fraction numerator 9 MR squared over denominator 2 end fraction minus MR squared over 18 equals space fraction numerator 81 space MR squared minus MR squared over denominator 18 end fraction equals space fraction numerator 40 space MR squared over denominator 9 end fraction

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