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Mechanical Properties Of Fluids

Question
CBSEENPH11020702

The total radiant energy per unit area, normal to the direction of incidence, received at a distance R from the centre of a star of radius r, whose outer surface radiates as a black body at a temperature T K is given by

  • σr2T4/R2

  • σr2T4/4πR2

  • σr4T4/r4

Solution

A.

σr2T4/R2

If r is the radius of the star and T its temperature, then the energy emitted by the star per second through radiation in accordance with Steafan's law will be given by 
AσT4 = 4πr2σ T4

In reaching a distance R this energy will spread over a sphere of radius R; so the intensity of radiation will be given by 

straight S space equals space fraction numerator straight P over denominator 4 πR squared end fraction space equals space fraction numerator 4 straight pi squared σT to the power of 4 over denominator 4 πR squared end fraction