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Mechanical Properties Of Fluids

Question
CBSEENPH11020700

An alpha nucleus of energy mv2/2 bombards a heavy nuclear target of charge Ze. Then the distance of closest approach for the alpha nucleus will be proportional to 

  • 1/Ze

  • v2

  • 1/m

  • 1/v4

Solution

C.

1/m

An α -  a particle of mass m possesses initial velocity when it is at large distance from the nucleus of an atom having atomic number Z. At the distance of closest approach, the kinetic energy of α - particle is completely converted into potential energy. Mathematically,

12mv2 = 14πε0(2e)(Ze)ror0 = 14πε02Ze212mv2 =1/m