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Laws Of Motion

Question
CBSEENPH11020639
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Force F on a particle moving in a straight line varies with distance d as shown in the figure. The work done on the particle during its displacement of 12 m is

  • 21 J

  • 26 J 

  • 13 J

  • 18 J

Solution

C.

13 J

Work done = Area under (F - x) graph
= 2 x (7-3) + space equals space 2 space straight x space left parenthesis 7 minus 3 right parenthesis space plus 1 half space straight x space 2 space straight x space left parenthesis 12 minus 7 right parenthesis equals space 8 space plus 1 half space straight x space 10 equals space 8 space plus space 5 space equals space 13 space straight J

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