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Mechanical Properties Of Fluids

Question
CBSEENPH11020630

When 1 kg of ice at 0oC  melts to water 0oC, the resulting change in its entropy, taking latent heat of ice to be 80 cal/oC, is

  • 8 x 104 cal /K

  • 80 cal/K

  • 293 cal/ K

  • 273 cal/ K

Solution

C.

293 cal/ K

Change in entropy

increment straight S space equals space ml over straight T space equals space fraction numerator 1000 space straight x space 80 over denominator 273 end fraction space equals space 293 space cal space straight K to the power of negative 1 end exponent