Question
Light of two different frequencies whose photons have energies 1 eV and 2.5 eV respectively illuminate a metallic surface whose work function is 0.5 eV successively. Ratio of maximum speeds of emitted electrons will be
-
1:2
-
1:4
-
1:5
-
1:1
Solution
A.
1:2
Here, KE1 = 1 - 0.5 = 0.5 eV
KE2 = 2.5 - 0.5 = 2 eV