The instantaneous angular position of a point on a rotation wheel is given by the equation

Q(t) = 2t³ - 6t²
The torque on the wheel becomes zero at

t = 0.5 s

t = 0.25 s

t = 2s

t = 1s

Solution

t = 1s

According space to space question comma space torque times straight tau space equals space 0 space it space means space that comma space straight alpha space equals space fraction numerator straight d squared straight theta over denominator dt squared end fraction Given space straight theta left parenthesis straight t right parenthesis space equals space 2 straight t cubed space minus space 6 straight t squared so space dθ over dt space equals space 6 straight t squared space minus space 12 straight t fraction numerator straight d squared straight theta over denominator dt squared space end fraction space equals space 12 straight t minus 12 open parentheses therefore space straight alpha space equals space fraction numerator straight d squared straight theta over denominator dt squared end fraction space equals space 0 close parentheses 12 straight t minus 12 space equals space 0 straight t space equals 1 straight s

Some More Questions From Units and Measurement Chapter

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