Question
A thermodynamic system is taken through the cycle ABCD as shown in a figure. Heat rejected by the gas during the cycle is
-
2 pV
-
4 pV
-
1/2 pV
-
pV
Solution
A.
2 pV
For given cyclic process, ΔU = 0
therefore, Q =W
Also, W = - area enclosed by the curve
= AB x AD
= (2p-p) (3V-V)
=-p x 2V
therefore,
Heat rejected = 2pV
