Question
A man of 50 kg mass standing in a gravity free space at height of 10 m above the floor. He throws a stone of 0.5 kg mass downwards with a speed 2 ms-1. When the stone reaches the floor, the distance of the man above the floor will be
-
9.9 m
-
10.1
-
10 m
-
20 m
Solution
B.
10.1
m r = constant
The distance of the man above the floor (total height) = 10+0.1 = 10.1
