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Motion In A Plane

Question
CBSEENPH11020691

A particle moves a distance x in time t according to equation x  = (t +5)-1. The acceleration of particle is proportional to

  • (velocity)3/2

  • (distance)2

  • (distance)-2

  • (velocity)2/3

Solution

A.

(velocity)3/2

Given, distance x = ( t + 5)-1   ...... (i)
Differentiating eq. (i) w.r.t, we get
dx over dt space equals space straight v space equals space fraction numerator negative 1 over denominator left parenthesis straight t plus 5 right parenthesis squared end fraction space space space space.... space left parenthesis ii right parenthesis

Again space comma space differentiating space eq space left parenthesis straight i right parenthesis thin space straight w. straight r. straight t comma space we space get
fraction numerator straight d squared straight x over denominator dt squared end fraction space equals space left parenthesis straight a right parenthesis space equals space fraction numerator 2 over denominator left parenthesis straight t space plus 5 right parenthesis cubed end fraction
Comparing space eqs. space left parenthesis ii right parenthesis space and space left parenthesis iii right parenthesis comma space we space get
left parenthesis straight a right parenthesis space proportional to space left parenthesis straight v right parenthesis to the power of 3 divided by 2 end exponent