Question

A particle moves a distance x in time t according to equation x = (t +5)^-1. The acceleration of particle is proportional to

(velocity)^3/2

(distance)²

(distance)^-2

(velocity)^2/3

Solution

(velocity)^3/2

Given, distance x = ( t + 5)^-1 ...... (i)
Differentiating eq. (i) w.r.t, we get
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Motion In A Plane

A particle moves a distance x in time t according to equation x = (t +5)^-1. The acceleration of particle is proportional to

(velocity)^3/2

(distance)²

(distance)^-2

(velocity)^2/3

Some More Questions From Motion in A Plane Chapter

For Daily Free Study Material Join wiredfaculty

Motion In A Plane

A particle moves a distance x in time t according to equation x = (t +5)-1. The acceleration of particle is proportional to (velocity)3/2 (distance)2 (distance)-2 (velocity)2/3

Some More Questions From Motion in A Plane Chapter

A particle moves a distance x in time t according to equation x = (t +5)^-1. The acceleration of particle is proportional to

(velocity)^3/2

(distance)²

(distance)^-2

(velocity)^2/3